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5. Final Preparatory Problems (April 21, 2006)

[Problems] WORD  PDF
[Solutions] WORD  PDF

4. Announcement of the Organizer(April 3, 2006)

The Solutions for the Preparatory Problems, which are not supposed to be  made public before June by the "Information for mentors at the International Chemistry Olympiad", have been inadvertently posted at this homepage since February 10, 2006. We have decided, after consulting with the International Steering Committee, to keep the Solutions posted as it is now for the sake of fairness

3. Revision on February 13, 2006

From: unclemax@inbox.lv

Dear members of IChO-2007 team, I have taken quick look at the preparatory problems and actually found a minor mistake.

In the Problem 5: Atmosphere of planets it is stated that gravitation potential energy can be calculated as GMm/R which is obviously wrong-the more the distance from the planet(R) the less poential energy(~1/r)? The actual formula for gravitation potential evergy is(-GMm/R).

Another point is that there is no phisical sense in equating the potential and kinetic energy. Explanation for 2nd cosmic velocity(the escape velocity)goes like this:at any point the equation for full mechanical energy is E = mv^2/2 - GMm/R which is assumed to be constant. Then if we assume that the molecule(the rocket) has escaped gravitation field of the Earth(i.e.is very far from it), them-GMm/R is ~ 0 (R is very large), and if we want to minimize th initial kinetic energy then we suppose that the body has stopped (mv^2/2 ~0). So E = 0 = mv(init.)^2/2 - GMm/R(earth), amd mv^2/2 = GMm/R.

Although these mechanical things do not really matter at the chemistry olympiad, I would be glad if you improved the task.


Sincerely yours,

Max Arzamasov, Student, Latvia

Revision2(Problems)

Revision2(Solutions)

2. Revision on Feburary 10, 2006

From: Andrej Gedec

Hi to you all. I hardly wait to see you and your country this year. But before that, we must do some job, and prepare our students.

And this is my question: I think I found two mistakes in physical chemistry preparatory problems and solutions (which we just get tuesday, thank you).

1. Problem 2: kinetic model of the gas. In calculating the volume of collision cylinder, we should use relative average speed, which is average speed, multiplied by square root of number two. So: V (cylinder) = sigma . v(relative) = sigma.sqrt(2). v (average). Then the solution of problem 2-2 and further problems is different for exactly square root of 2 (compared to the solutions you sent us).

2. Problem 36: on the page 73, there is description of the Michaelis Menten mechanism, and solving for (ES) (second line up from bottom of the page) gives just Km in the denominator, and not Km+(S), as it stands in description.

Please pass my comment to the person in charge of the preparation of the problems. 

In general, the problems are very good and connected to real life. Especially I like the introduction, where the subject is inner and outer space.

Thank you, and see you soon


Sincerely yours

Andrej Godec,mentor,Slovenia, Europe 

Re: preparatory problems

Andrei Godec, mentor of Slovenia, kindly pointed out mistakes in Problem 2 and 36. His points were well taken and corrections were made in the posted web versions.
 

        Problem 2: In caculating the volume of the collision cylinder, one needs to multiply the average speed by square root of 2 in consideration of the relative motion of the atoms. It was left out purposely for the initial order of magnitude calculations. We agree that 40% is a significant difference particularly when dealing with billions of years.
 

      Problem 36: There was a simple typographical error.

We really appreciate your comments. Many thanks to Mr. Godec.

Revision(Problems)

Revision(Solutions)

1. Preparatory Problems (January 24, 2006)

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